plb2800: Return 1 from plb2800_eth_initialize() upon successful initialization and 0 in case of failure

Signed-off-by: Matthias Kaehlcke matthias@kaehlcke.net --- drivers/net/plb2800_eth.c | 4 ++-- 1 files changed, 2 insertions(+), 2 deletions(-)

diff --git a/drivers/net/plb2800_eth.c b/drivers/net/plb2800_eth.c index d799c73..ccbced2 100644 --- a/drivers/net/plb2800_eth.c +++ b/drivers/net/plb2800_eth.c @@ -106,7 +106,7 @@ int plb2800_eth_initialize(bd_t * bis) if (!(dev = (struct eth_device *) malloc (sizeof *dev))) { printf("Failed to allocate memory\n"); - return -1; + return 0; } memset(dev, 0, sizeof(*dev));

@@ -141,7 +141,7 @@ int plb2800_eth_initialize(bd_t * bis) printf("Leaving plb2800_eth_initialize()\n"); #endif

- return 0; + return 1; }

static int plb2800_eth_init(struct eth_device *dev, bd_t * bis)