Re: [U-Boot] Entry point for uncompressed kernel image
Hi , I am getting an exception once I try to boot the image with bootm command. Boardcon> bootm 30008000 ## Booting image at 30008000 ... Image Name: Created: 2011-01-07 6:04:55 UTC Image Type: ARM Linux Kernel Image (uncompressed) Data Size: 3035360 Bytes = 2.9 MB Load Address: 30008000 Entry Point: 30008000 Verifying Checksum ... OK XIP Kernel Image ... OK
initrd_start:0 ,initrd_end : 0 ## Transferring control to Linux (at address 30008000) ...
Starting kernel ...30008000
bd->bi_arch_number:168 , bd->bi_boot_params:805306624data abort pc : [<30008010>] lr : [<33d9f098>] sp : 33d3da98 ip : ffffffff fp : 00000000 r10: 00000001 r9 : 00000000 r8 : 33d3ffdc r7 : 00000000 r6 : 33de2f84 r5 : 33d409e2 r4 : 00000000 r3 : 30008000 r2 : 30000100 r1 : 000000a8 r0 : ea000016 Flags: nZCv IRQs off FIQs off Mode SVC_32 Resetting CPU ...
The above is an uncompressed kernel image with load and entry point as 30008000. Can you suggest with how I can debug the issue. thanks & regardsGIGIN --- On Fri, 7/1/11, Pankaj Pandey pankaj.embedded@gmail.com wrote:
From: Pankaj Pandey pankaj.embedded@gmail.com Subject: Re: [U-Boot] Entry point for uncompressed kernel image To: "Gigin Jose" gigin_jose@yahoo.co.in Date: Friday, 7 January, 2011, 10:52 AM
hi ....u can define same 0x30008000 as entry and load address.
Regards, Pankaj Pandey
On Fri, Jan 7, 2011 at 2:07 PM, Gigin Jose gigin_jose@yahoo.co.in wrote:
Hi ,
I am trying to put uncompressed kernel image to SDRAM for my s3c2440 development board. The uncompressed kernel image is made from 'Image' inside arch/arm/boot folder using the mkimage tool.
What should be the entry point and load address for the uncompressed kernel image ?
The physical address of my RAM is 0x30000000 and the zImage is loaded to the address 0x30008000.
thanks & regardsGIGIN
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