Hi All,

I was trying to understand the boot sequence on the BF537.

The TEXT_BASE = ( 0x03FC0000, 0x01FC0000 ). This address is located in the region of "SDRAM" on the "SMS0" of the "EBUI"

How or where do we program the "u-boot" image that is generated, so that it will be copied to the "SDRAM" location.

Are we expecting the "BootROM" loader file to do this ? Who does the "SDRAM" initializations ?

Warm Regards, Raghu.

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