In message BAY2-F35dSZwnUdfnuz000953d6@hotmail.com you wrote:

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...

How do you know that? And what exactly means "stuck" in this context?

I put the following piece of code in head_4xx.S:

...

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early_init is the c functional. From the console I can see '1' but no

'2',

...

which is expected after early_init is done.

What you write is true, although you didn't mean it:

It is indeed expected that you don't see '2', because your code just crashes the system.

Really!? I didn't realize this!! Could you give some more detail? Why the code could crash the system? In order to use the UART, I also added a TLB entry as below:

/* Set up a TLB for UART controller */ lis r3, UART0_BASE@h addi r3, r3, UART0_BASE@l

ori r4, r3, 0

clrrwi r4, r4, 10 ori r4, r4, (TLB_WR | TLB_EX | TLB_I | TLB_G)

clrrwi r3,r3,10 /* Mask off the effective page number */ ori r3,r3,(TLB_VALID | TLB_PAGESZ(PAGESZ_4K))

li r0, 11

tlbwe r4, r0, TLB_DATA tlbwe r3, r0, TLB_TAG sync

Best regards, Frank

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