In message 60E856FD577CC04BA3727AF4122D3F160123856C@3bit.vector.com.pl you wrote:
for some reason we need to replace flash chip on yellowstone board and program it with external programmer. The question is that for external programmer flash is visible as 0-64M, and I'm not sure where should I program 512k of u-boot? I assume that at the end of the chip (CPU is looking at the end, at 0xfffffffc),am I right?
The normale image address for U-Boot on the yelowstone is FFF80000 (flash being mapped ion the FC000000 ... FFFFFFFF area); so if you see 0 ... 64M = 04000000, then you will have to program the image at 0x3F80000
Also concerning endianness -as board has swapped data and address signals (flash_A0->cpu_A30, flash_D0->cpu_D15) I assume that image
There are no swapped signals. Just keep in mind that on PowerPC MSB = Bit 0.
can be programmed "as is" - 16-bit word-by-word without any conversion? Please fix me if I'm wrong.
Right.
Best regards,
Wolfgang Denk