On Wednesday 14 November 2012 07:02 PM, R Sricharan wrote:
On Wednesday 14 November 2012 02:19 PM, Lokesh Vutla wrote:
DMM_LISA_MAP registers program whether memory is mapped on particular EMIF or not. Irrespective of these registers EMIF is getting configured. Correcting the same.
Signed-off-by: Lokesh Vutla lokeshvutla@ti.com
arch/arm/cpu/armv7/omap-common/emif-common.c | 39 ++++++++++++++++++++++---- 1 file changed, 34 insertions(+), 5 deletions(-)
diff --git a/arch/arm/cpu/armv7/omap-common/emif-common.c b/arch/arm/cpu/armv7/omap-common/emif-common.c index 30dcf1b..179525f 100644 --- a/arch/arm/cpu/armv7/omap-common/emif-common.c +++ b/arch/arm/cpu/armv7/omap-common/emif-common.c @@ -33,6 +33,8 @@ #include <asm/utils.h> #include <linux/compiler.h>
+static int emif1_enabled = -1, emif2_enabled = -1;
- void set_lpmode_selfrefresh(u32 base) { struct emif_reg_struct *emif = (struct emif_reg_struct *)base;
@@ -1218,6 +1220,27 @@ void dmm_init(u32 base) } }
+static void enable_emifs(void) +{
- u32 i, section, valid;
- emif1_enabled = 0;
- emif2_enabled = 0;
- for (i = 0; i < 4; i++) {
section = __raw_readl(DMM_BASE + i*4);valid = (section & EMIF_SDRC_MAP_MASK) >>(EMIF_SDRC_MAP_SHIFT);if (valid == 1) {emif1_enabled = 1;} else if (valid == 2) {emif2_enabled = 1;} else if (valid == 3) {emif1_enabled = 1;emif2_enabled = 1;return;}- }
+} /*
- SDRAM initialization:
- SDRAM initialization has two parts:
@@ -1255,15 +1278,21 @@ void sdram_init(void) writel(CM_DLL_CTRL_NO_OVERRIDE, &prcm->cm_dll_ctrl); }
- do_sdram_init(EMIF1_BASE);
- do_sdram_init(EMIF2_BASE);
if (!in_sdram) dmm_init(DMM_BASE);
- enable_emifs();
The function name is odd. It has got nothing to do with enabling EMIF's. It just identifies which is enabled ?. How about set_enabled_emifs ?
Also this can done just when you are configuring the LISA registers. That way a extra function is avoided.
Yes you are right. Ill do this post it.
Thanks Lokesh
Regards, Sricharan