
19 May
2008
19 May
'08
3:22 a.m.
On 01:03 Mon 19 May , Wolfgang Denk wrote:
In message 20080518222019.GC19480@game.jcrosoft.org you wrote:
static inline void *memcpy(void *dst, const void *src, unsigned int len) { char *ret = dst;
- while (len-- > 0) { *ret++ = *((char *)src); src++; }
- return (void *)ret;
- return (void *)dst;
While technically correct, this is bogus. We have a variable ret, but we don't return it. And we have a variable dst, but we don't use it as destination pointer.
Please change the *ret++ = *((char *)src); into *dst++ = *((char *)src); and leave all the rest.
You can not do this because dst is a void
Why not? src is void, too.
gcc will claim about the cast.
we can do this void *ret = dst; char *d = dst; const char *s = src;
while (len-- > 0) *d++ = *s++;
return ret;
Best Regards, J.