23 Aug
2009
23 Aug
'09
9:30 p.m.
Dear Mike Frysinger,
In message 200908230209.10484.vapier@gentoo.org you wrote:
this check will fail with binutils 3.0+ because of the minor check for 16 without a corresponding major check.
Well, the "\1 -lt 2" is the major check, isn't it?
here is how the shell code looks: [ $major -lt 2 ] || [ $minor -lt 16 ] && echo old_ld
Oops.
and the way shell logic works, the echo is executed if either of those tests fail. what you really wanted was: [ $major -lt 2 ] || [ $major -eq 2 -a $minor -lt 16 ] && echo old_ld
Right you are. Silly me.
Thanks for catching this in time.
Best regards,
Wolfgang Denk
--
DENX Software Engineering GmbH, MD: Wolfgang Denk & Detlev Zundel
HRB 165235 Munich, Office: Kirchenstr.5, D-82194 Groebenzell, Germany
Phone: (+49)-8142-66989-10 Fax: (+49)-8142-66989-80 Email: wd@denx.de
In general, they do what you want, unless you want consistency.
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