19 Nov
2023
19 Nov
'23
10:28 p.m.
Hi Benjamin,
[Please do not top-post]
On Sun, Nov 19, 2023 at 6:08 PM Szőke Kálmán Benjamin egyszeregy@freemail.hu wrote:
(void)(devno); is need because devno arguments is an unused variable, need to use this solution to suppress any potential warnings.
No, devno is a function parameter. There is no warning if '(void)(devno)' is removed.