yaojin liu wrote:
thanks，you are right, it really init the chip through UBL. BUT, there is also one question: DM9000a 's driver has 8 bit accessing function:
#define CONFIG_DM9000_BASE 0x04000000 #define DM9000_IO CONFIG_DM9000_BASE #define DM9000_DATA (CONFIG_DM9000_BASE+2) // (BA1,it's the 16bit least significant bit (effective) ) #define DM9000_outb(d,r) ( *(volatile u8 *)r = d ) #define DM9000_inb(r) (*(volatile u8 *)r) static u8 DM9000_ior(int reg) { DM9000_outb(reg, DM9000_IO); return DM9000_inb(DM9000_DATA); }
/* Write a byte to I/O port */ static void DM9000_iow(int reg, u8 value) { DM9000_outb(reg, DM9000_IO); DM9000_outb(value, DM9000_DATA); } and the davinci's chipselect space is 16bit. when accessing it as 8bit ,the last bit(may be A-2 ?) will be effective, but the least significant bit(BA1) will not be effective, am i wrong? how does it work?
I think this is a no-problem, because the DM9000 has two separate area for registers and data. As you check in the driver, the bus width is checked and the driver has internal accessors (dm9000_outblk_*) to adapt itself to the different bus size.
To access internal registers, it is required to write to DM9000_IO the registers offset, and the DM9000 store the register index internally that should be read/changed with the next access. So registers are not accessed directly, you have to program which you want. And the DM9000 takes the LSB of the data bus as register offset.
Best regards, Stefano Babic