5 Feb
2010
5 Feb
'10
7:42 a.m.
Dear "Gupta, Ajay Kumar",
In message 19F8576C6E063C45BE387C64729E7394044A776008@dbde02.ent.ti.com you wrote:
Opps, there are actually 32 intermediate register each of 32 bits.
So the correct one is as Neal suggested.
- u32 reserved[0x20];
- u32 reserved[020/4];
0x20 / 4 = 8
020 / 4 = 4
Best regards,
Wolfgang Denk
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