
Hi Marek,
On Wed, 13 Oct 2021 at 09:46, Marek Behún kabel@kernel.org wrote:
From: Marek Behún marek.behun@nic.cz
Since we no longer use env_get_char() to access n-th character of linearized environment data, but rather access the arrays themselves, we can convert the iteration to use string pointers instead of position indexes.
Signed-off-by: Marek Behún marek.behun@nic.cz
cmd/nvedit.c | 34 +++++++++++++++++----------------- 1 file changed, 17 insertions(+), 17 deletions(-)
diff --git a/cmd/nvedit.c b/cmd/nvedit.c index 7c99a693ea..6eabd51209 100644 --- a/cmd/nvedit.c +++ b/cmd/nvedit.c @@ -706,17 +706,17 @@ char *from_env(const char *envvar) return ret; }
-static int env_match(const char *env, const char *s1, int i2) +static const char *matching_name_get_value(const char *p, const char *name)
OK so this is the function where I would like a nice comment, please.
{
while (*s1 == env[i2++] && *s1 != '\0')
if (*s1++ == '=')
return i2;
while (*name == *p++ && *name != '\0')
if (*name++ == '=')
return p;
/* We can look at env[i2-1] because i2 was incremented at least once. */
if (*s1 == '\0' && env[i2-1] == '=')
return i2;
/* We can look at p[-1] because p was incremented at least once. */
if (*name == '\0' && p[-1] == '=')
return p;
return -1;
return NULL;
}
/* @@ -724,8 +724,7 @@ static int env_match(const char *env, const char *s1, int i2) */ int env_get_f(const char *name, char *buf, unsigned len) {
const char *env;
int i, nxt;
const char *env, *p, *nxt; if (name == NULL || *name == '\0') return -1;
@@ -735,20 +734,21 @@ int env_get_f(const char *name, char *buf, unsigned len) else env = (const char *)gd->env_addr;
for (i = 0; env[i] != '\0'; i = nxt + 1) {
int val, n;
for (p = env; *p != '\0'; p = nxt + 1) {
const char *value;
int n;
for (nxt = i; env[nxt] != '\0'; ++nxt)
if (nxt >= CONFIG_ENV_SIZE)
for (nxt = p; *nxt != '\0'; ++nxt)
if (nxt - env >= CONFIG_ENV_SIZE) return -1;
val = env_match(env, name, i);
if (val < 0)
value = matching_name_get_value(p, name);
if (value == NULL) continue; /* found; copy out */ for (n = 0; n < len; ++n, ++buf) {
*buf = env[val++];
*buf = *value++; if (*buf == '\0') return n; }
-- 2.32.0
Regards, Simon