
25 Jul
2008
25 Jul
'08
1:44 p.m.
Jerry Van Baren wrote:
So you should be able to use 0xE0800000..0xE0FFFFFF - 2nd "copy" of the first bank 0xE1000000..0xE17FFFFF - 1st "copy" of the second bank you will double your available consecutive memory. You can do the same thing with the third and fourth banks of memory, but you will still have a gap between the first pair and second pair. This will reduce your four fragments / three holes to two fragments / one hole. Solved half your problem anyway. 0xE4800000..0xE4FFFFFF - 2nd "copy" of the first bank 0xE5000000..0xE57FFFFF - 1st "copy" of the second bank
doh! ^^^^^^
s/first/third/ s/second/fourth/
Sorry for the cut&paste error. gvb