On Tuesday 10 June 2008, Shinya Kuribayashi wrote:
Shouldn't this be the other way around?
if (board_eth_init(bis) < 0)eth_eth_init(bis);So that the board init routine can "overwrite" the cpu init version.
Yeah, I think you're right. If board_eth_init() exists, it gets highest priority.
Just wondered, does that mean we could only have either cpu_eth_init or board_eth_init at a time?
Not really. board_eth_init() could call cpu_eth_init() if necessary.
Best regards, Stefan
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