Dear ba_f,
In message 5c515fb3b2f956768d10d2e2c2e9402e@rbg.informatik.tu-darmstadt.de you wrote:
But the kernel crushes pretty early with the following u-boot output:
## Starting application at 0x01000000 ... ## Application terminated, rc = 0x1
This is NOT a crash. The program terminates normally with a return code of 1.
What may cause "Application terminated, rc = 0x1"?
Something that takes the same effect as "return(1)" from your main() function, resp. an "exit(1)" from other parts of the code.
I don't think it is a regular code exit, like main(){ return 1; }.
But yes, it is. From the line
## Application terminated, rc = 0x1
you can see that the program returned normally to U-Boot, and U-Boot continues running (unless your code destroyed any of the U-Boot execution environment).
Best regards,
Wolfgang Denk