Hi Heinrich,
On Sat, 9 Nov 2024 at 03:31, Heinrich Schuchardt heinrich.schuchardt@canonical.com wrote:
Before this patch the sandbox uses 0xffffffea as PXE architecture.
=> efidebug defaults Default boot path: EFI\BOOT\BOOTSBOX.EFI PXE arch: 0xffffffeaWith this patch it uses the PXE architecture that matches the host. This allows us to use bootmeth EFI on the sandbox to load an EFI binary.
Signed-off-by: Heinrich Schuchardt heinrich.schuchardt@canonical.com
lib/efi_loader/efi_helper.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-)
The way things are, this isn't a valid thing to do. It is returning an error to indicate that. The error should be checked. If you use -N then it will do what you want, though.
But what architectures does this work for, with your setup? I haven't been able to get x86_64 to work. I could perhaps try arm64?
Should we document this use of sandbox for your use case, once it is working?
diff --git a/lib/efi_loader/efi_helper.c b/lib/efi_loader/efi_helper.c index bf96f61d3d0..14049378930 100644 --- a/lib/efi_loader/efi_helper.c +++ b/lib/efi_loader/efi_helper.c @@ -75,7 +75,7 @@ const char *efi_get_basename(void)
int efi_get_pxe_arch(void) {
if (efi_use_host_arch())
if (IS_ENABLED(CONFIG_SANDBOX)) return HOST_PXE_ARCH; /* http://www.iana.org/assignments/dhcpv6-parameters/dhcpv6-parameters.xml */-- 2.45.2
Regards, Simon