Dear Vinoth,
In message CAJst-kFZjA_Nq7K25CEPri9Aq7r=-mmtGyeNYwwg-P2CrN4dbA@mail.gmail.com you wrote:
I am using the following command to create uImage. Here in the architecture argument I am not seeing any option corresponding to the Intel-x86_64. So I had used x86, which I am not sure is valid or not. The kernel is 64 bit.
mkimage -A x86 -O linux -T kernel -C none -a 0x100000 -e 0x00000 -n Linux -d vmlinux-4.4.6-ina uImage Image Name: Linux Created: Fri Jun 24 10:35:40 2016 Image Type: Intel x86 Linux Kernel Image (uncompressed) Data Size: 21966248 Bytes = 21451.41 kB = 20.95 MB Load Address: 00100000 Entry Point: 00000000
This makes no sense to me. When the kernel image is loaded to RAM starting at address 0x00100000, then ther eis no valid code at address 0x00000000. So 0x00000000 cannot be a valid entry oint address. The entry point address must be somewhare in the range between "load address" and "load address + size of uncompressed kernel image".
Error: Invalid Boot Flag (found 0x0000, expected 0xaa55) Setup at 0x000000 Magic signature not found
Is is I need to load setup.bin also?
I have no idea. I didn't know that you were asking for x86... I'm not an expert in this area. I added Simon and Bin to cc: who might be in a much better position to answer such a question.
Best regards,
Wolfgang Denk