From: Alessandro Rubini rubini@unipv.it
If source and destination are aligned, this copies ulong values until possible, trailing part is copied by byte. Thanks for the details to Wolfgang Denk, Mike Frysinger, Peter Tyser, Chris Moore.
Signed-off-by: Alessandro Rubini rubini@unipv.it Acked-by: Andrea Gallo andrea.gallo@stericsson.com Acked-by: Mike Frysinger vapier@gentoo.org --- lib_generic/string.c | 19 +++++++++++++++---- 1 files changed, 15 insertions(+), 4 deletions(-)
diff --git a/lib_generic/string.c b/lib_generic/string.c index 181eda6..61a45dc 100644 --- a/lib_generic/string.c +++ b/lib_generic/string.c @@ -446,12 +446,23 @@ char * bcopy(const char * src, char * dest, int count) * You should not use this function to access IO space, use memcpy_toio() * or memcpy_fromio() instead. */ -void * memcpy(void * dest,const void *src,size_t count) +void * memcpy(void *dest, const void *src, size_t count) { - char *tmp = (char *) dest, *s = (char *) src; - + unsigned long *dl = (unsigned long *)dest, *sl = (unsigned long *)src; + char *d8, *s8; + + /* while all data is aligned (common case), copy a word at a time */ + if ( (((ulong)dest | (ulong)src) & (sizeof(*dl) - 1)) == 0) { + while (count >= sizeof(*dl)) { + *dl++ = *sl++; + count -= sizeof(*dl); + } + } + /* copy the reset one byte at a time */ + d8 = (char *)dl; + s8 = (char *)sl; while (count--) - *tmp++ = *s++; + *d8++ = *s8++;
return dest; }